Team India gives Kohli guard of honour in batter’s 100th Test

Rohit Sharma-led Team India on Saturday gave a guard of honour to maverick batter Virat Kohli in the batter’s 100th Test. When India walked out to the field on Day

Rohit Sharma-led Team India on Saturday gave a guard of honour to maverick batter Virat Kohli in the batter’s 100th Test.

When India walked out to the field on Day 2 of the ongoing Test against Sri Lanka here in Mohali, the entire Team stood together to give Kohli a guard of honour.

Kohli scored 45 runs in the first innings of the ongoing Test and he was dismissed by Lasith Embuldeniya.

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Ravindra Jadeja scored an unbeaten 175 as India declared their first innings at 574/8 against Sri Lanka.

Resuming the second session at 468/7, India lost its eighth wicket quite early as Vishwa Fernando sent Jayant Yadav (2) back to the pavilion.

However, Ravindra Jadeja kept on scoring runs at a brisk pace. The left-handed batter brought up his 150 in the 123rd over of the innings.

Jadeja scored an unbeaten 175 and Rohit Sharma finally declared the innings with the score being 574/8. Sri Lanka was made to bowl 129.2 overs in the first innings.

Along with Jadeja, Mohammed Shami also remained unbeaten on 20. 

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